Problem: Given an n-ary tree, return the level order traversal of its nodes' values.
Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value (See examples).
Example:
Input: root = [1,null,3,2,4,null,5,6] Output: [[1],[3,2,4],[5,6]]
Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14] Output: [[1],[2,3,4,5],[6,7,8,9,10],[11,12,13],[14]]
Approach: Like in case of binary tree's level order traversal, we will use queue here. The approach is same.
Implementation in C#:
public IList<IList<int>> LevelOrder(Node root)
{
List<IList<int>> result = new List<IList<int>>();
if (root == null)
{
return result;
}
Queue<Node> queue = new Queue<Node>();
queue.Enqueue(root);
while(queue.Count > 0)
{
List<int> currRow = new List<int>();
int size = queue.Count;
for (int i = 0; i < size; ++i)
{
var node = queue.Dequeue();
currRow.Add(node.val);
foreach(var child in node.children)
{
queue.Enqueue(child);
}
}
result.Add(currRow);
}
return result;
}
Complexity: O(n)
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