Problem: You are given a license key represented as a string S which consists only alphanumeric character and dashes. The string is separated into N+1 groups by N dashes.
Given a number K, we would want to reformat the strings such that each group contains exactly K characters, except for the first group which could be shorter than K, but still must contain at least one character. Furthermore, there must be a dash inserted between two groups and all lowercase letters should be converted to uppercase.
Given a non-empty string S and a number K, format the string according to the rules described above.
Example:
Input: S = "5F3Z-2e-9-w", K = 4 Output: "5F3Z-2E9W" Explanation: The string S has been split into two parts, each part has 4 characters. Note that the two extra dashes are not needed and can be removed.
Input: S = "2-5g-3-J", K = 2 Output: "2-5G-3J" Explanation: The string S has been split into three parts, each part has 2 characters except the first part as it could be shorter as mentioned above.
Approach: The approach is straight forward. You can understand it by just looking at the code.
Implementation in C#:
public string LicenseKeyFormatting(string S, int K)
{
S = S.Replace("-", "");
if (string.IsNullOrWhiteSpace(S))
{
return "";
}
int length = S.Length;
int charsinFirstGroup = length % K == 0 ? K : length % K;
StringBuilder builder = new StringBuilder();
int j = 0;
for (int i = 0; i < charsinFirstGroup; ++i)
{
builder.Append(char.ToUpper(S[j++]));
}
builder.Append('-');
while (j < length)
{
for (int i = 0; i < K; ++i)
{
builder.Append(char.ToUpper(S[j++]));
}
builder.Append('-');
}
builder.Length--;
return builder.ToString();
}
Complexity: O(n)
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